# Here I’m going to propose a **new strategy** to perform the typical 1:1 roulette bets (colors, odd, even, 1-18 and 19-36). It is based on the analysis presented previously for the zero number. If you have not read that post, please read it. Because Zero is one of the most feared numbers when 1:1 bets are performed and it is important to know about it.

Before presenting the strategy, there are **some important facts** you should know about 1:1 bets:

- The probability of win this kind of bets (1:1 bets) on European roulette is 48.65% for each independent roulette spin. This means that in each roulette spin you have a 51.35% against you.
- Theoretical maximum delay of these bets is 7 roulette spins (read about delay in the roulette here). The next picture shows how the probability of occurrence is increased each time the 1:1 numbers are delayed.
- Next table shows how many roulette spins are expected before a repetition of the same kind of 1:1 numbers occur. It shows that it is very possible that after 17 roulette spins a 1:1 number (same color, odd, even 1-18 or 19-3) will be repeated. Obviously, its opposed bet will be delayed. For example, after 17 roulette spins it is possible that red color appears two times, so black color will be delayed.

Consecutive occurrence | Spins | Time [hours] |

1 | 7 | 0.1 |

2 | 17 | 0.3 |

3 | 38 | 0.6 |

4 | 80 | 1.3 |

5 | 167 | 2.8 |

6 | 345 | 5.8 |

7 | 712 | 11.9 |

Please check that playing one roulette spin per minute an important delay (7 roulette spins) will occur each 12 hours. At least two times a day.

If you have read the post about the zero number, the delay on roulette, and these facts about 1:1 bets now you are ready to understand the strategy.

**Pay attention please, I will explained in four easy steps.**

- Wait until zero appears. In theory, this will give us 27 roulette spins without annoying zeros. After the first zero appears you have to count the roulette spins. Remember you have only 27 spins before zero comes back (probablilistically, I meant).
- After the zero appears wait for any 1:1 bet to appear twice consecutive. You should have money enough to endure at least for 5 consecutive lost games (Just in case of 7 roulette spins of delay, remember that it happens twice a day).
- Bet with your favorite betting system (martingale, D’Alember, Labouchere etc).
- If you finish your betting system return to point 2. It is important to plan short strategies. If it has been 27 roulette spins, try to finish as fast as you can because it is possible that zero appears again.

The bet is considered finished once you have reached the profit you want. Finally I also recommend the post about preparing your bets.

**Here I present the strategy with real data obtained in a real casino.**

**Labouchere example:**

We set a sequence of numbers that would guide us along the bets. In this case 5,5,5,5,5 (This sequence can be as long as you want and you can change the amount of each number).

we always going to bet the sum of the first and the last numbers. In this case our first bet would be 5+5=10

In case we win the bet, the first and the last number disappear and our sequence is now: 5,5,5 and our next bet would be 5+5=10

In case we lose, we have to add the amount lost at the end of the sequence: 5,5,5,5,5,10 and our next bet would be 5+10=15.

The cycle is repeated until all numbers disappear.

**Applying the scheme presented in this post:**

We have to wait until get zero.

Spin | Result | My bet | My Count | Win |

1 | 34 | - | 0 | - |

2 | 7 | - | 0 | - |

3 | 0 | - | 0 | - |

Now, count the spins and wait for two repetitions on 1:1 bets. (1 and 21 both red).

Spin | Result | My bet | My count | Win |

4 | 1 | - | 1 | - |

5 | 21 | - | 2 | - |

**Lets begin the bets.**

The first sequence: 5,5,5,5. Bet 10 to black. The count is 3 spins after zero. Result: black, we win.

New sequence: 5,5. Bet 10 to black. The count is 4 spins after zero. Result red, we lose.

New sequence: 5,5,10. Bet 15 to black. The count is 5 spins after zero. Result: black, we win.

New sequence: 5,5. Bet 10 to black. The count is 6 spins after zero. Result red, we lose.

New sequence: 5,5,10. Bet 15 to black. The count is 7 spins after zero. Result red, we lose.

New sequence: 5,5,10,15. Bet 20 to black. The count is 8 spins after zero. Result: black, we win.

New sequence: 5,10. Bet 15 to black. The count is 9 spins after zero. Result: black, we win and the sequence is over.

Spin | Result | My bet | My count | Win |

6 | 8 | 10 | 3 | Yes |

7 | 7 | 10 | 4 | No |

8 | 31 | 15 | 5 | Yes |

9 | 32 | 10 | 6 | No |

10 | 9 | 15 | 7 | No |

11 | 4 | 20 | 8 | Yes |

12 | 17 | 15 | 9 | Yes |

We have 18 spins before the theoretically occurrence of the zero. We have two options: 1) wait for the next zero and begin again and 2) continue betting until 27 spins.

I recommend to stop here and return other day. **Remember, the less time you spend in the casino the less opportunity to lose your money.**

**D’Alembert example:**

For this bet we only have to set two parameters: Base bet and an profits target.

Let’s say that we set the base in 5 and expect to earn 25.

In case we win, we continue betting 5 until get the profits target.

In case we lose, we just add one unit. Our new bet would be 5+1=6

*Applying the scheme presented in this post:*

We have to wait until get zero.

Spin | Result | My bet | My count | Win |

1 | 0 | - | 0 | - |

Now, count the spins and wait for two repetitions on 1:1 bets. (28 and 4 both black).

Spin | Result | My bet | My count | Win |

2 | 28 | - | 1 | - |

3 | 4 | - | 2 | - |

**Lets begin the bets.**

Our first bet: 5 to red. The count is 4 spins after zero. Result: red, we win. Profits: 5

New bet: 5 to red. The count is 5 spins after zero. Result red, we win. Profits: 10.

New bet: 5 to red. The count is 6 spins after zero. Result red, we win. Profits: 15.

New bet: 5 to red. The count is 7 spins after zero. Result red, we win. Profits: 20.

New bet: 5 to red. The count is 8 spins after zero. Result black, we lose. Profits: 15.

New bet: 6 to red. The count is 9 spins after zero. Result black, we lose. Profits: 9.

New bet: 7 to red. The count is 10 spins after zero. Result red, we win. Profits: 16.

New bet: 5 to red. The count is 11 spins after zero. Result red, we lose. Profits: 11.

New bet: 6 to red. The count is 12 spins after zero. Result red, we win. Profits: 17.

New bet: 5 to red. The count is 13 spins after zero. Result red, we win. Profits: 22.

New bet: 5 to red. The count is 14 spins after zero. Result red, we win. Profits: 27. Minimum profit obtained.

Spin | Result | My bet | My count | Win |

4 | 16 | 5 | 4 | Yes |

5 | 19 | 5 | 5 | Yes |

6 | 31 | 5 | 6 | Yes |

7 | 29 | 5 | 7 | Yes |

8 | 15 | 5 | 8 | No |

9 | 31 | 6 | 9 | No |

10 | 5 | 7 | 10 | Yes |

11 | 31 | 5 | 11 | No |

12 | 12 | 6 | 12 | Yes |

13 | 1 | 5 | 13 | Yes |

14 | 1 | 6 | 14 | Yes |

We have 14 spins before the theoretically occurrence of the zero. We have two options: 1) wait for the next zero and begin again and 2) continue betting until 27 spins.

## As before, I recommend to stop here and return other day. **Once again remember, the less time you spend in the casino the less opportunity to lose your money.**